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Severt Seymour 1854 — 1895

Born on 1854 Severt Seymour passed away on Apr 1895, at the age of 41 and was buried in Mamrelund Cemetery in Hamilton County, IA. Severt Seymour was married to Elizabeth "lizzy" Jacobs Seymour and had 1 children: Mabel F Seymour Mccomb.

Birth:
1854
Death:
Apr 1895 (aged 41)
Burial place:
Mamrelund Cemetery
Iowa

Passed away Relatives of Severt Seymour

spouses

1859 — 1935 (aged 76)
Burial place:
Address:
Iowa

children

1888 — 1967 (aged 79)
Burial place:
Address:
Blairsburg, IA
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Who is Else Buried at Mamrelund Cemetery in Iowa

1887 — 1895 (aged 8)
Birth place:
Randall, IA
1843 — 1923 (aged 79)
Died 1873
1893 — 1978 (aged 84)
1930 — 2002 (aged 71)
1888 — 1961 (aged 72)
1915 — 2003 (aged 88)
1910 — 1989 (aged 79)
Birth place:
Iowa
1893 — 1904 (aged 11)
1864 — 1944 (aged 80)
1909 — 1972 (aged 63)
1894 — 1990 (aged 95)
See all burial records

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FAQ

When was Severt Seymour born?

Severt Seymour was born on 1854

When did is Severt Seymour pass away?

Severt Seymour passed away in April 1895

Where is Severt Seymour buried?

Severt Seymour is interred in Hamilton County, Iowa

At what age did Severt Seymour pass away?

Severt Seymour passed away at the age of 41

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