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Ruby Lee Ballard Seymour 1910 — 1988

Born on 1910 Ruby Lee Ballard Seymour passed away on 1988, at the age of 78 and was buried in Sidney Cemetery in Sidney, IA. Ruby Lee Ballard Seymour was married to Alfred Seymour and had 1 children: Albert Lee Seymour.

Birth:
1910
Death:
1988 (aged 78)
Plot:
Sec 5
Burial place:
Sidney Cemetery
Sidney, IA

Passed away Relatives of Ruby Lee Ballard Seymour

spouses

1909 — 1985 (aged 76)
Burial place:
Address:
Sidney, IA

children

1933 — 1954 (aged 20)
Burial place:
Address:
Sidney, IA
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Who is Else Buried at Sidney Cemetery in Iowa

1874 — 1969 (aged 95)
1921 — 1989 (aged 68)
Birth place:
Iowa
1929 — 1929 (aged less than a year)
1833 — 1887 (aged 54)
1906 — 1991 (aged 85)
1911 — 1947 (aged 36)
1895 — 1953 (aged 58)
1899 — 1987 (aged 87)
Birth place:
Nebraska
1918 — 2007 (aged 88)
1891 — 1980 (aged 88)
Birth place:
Red Oak, IA
1871 — 1902 (aged 30)
1913 — 1991 (aged 77)
Birth place:
Montana
1876 — 1964 (aged 87)
1841 — 1920 (aged 78)
Birth place:
Indiana
1823 — 1899 (aged 76)
1917 — 2010 (aged 93)
1925 — 1972 (aged 46)
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FAQ

When was Ruby Lee Ballard Seymour born?

Ruby Seymour was born on 1910

When did is Ruby Lee Ballard Seymour pass away?

Ruby Seymour passed away in 1988

Where is Ruby Lee Ballard Seymour buried?

Ruby Seymour is interred in Sidney, IA, in Plot: Sec 5

At what age did Ruby Lee Ballard Seymour pass away?

Ruby Seymour passed away at the age of 78

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