Powered by TF

Laban F Bryant 1862 — 1890

Born on Feb 11, 1862 Laban F Bryant passed away on Sep 23, 1890, at the age of 28 and was buried in Oakwood Cemetery in Honey Grove, TX.

Birth:
Feb 11, 1862
Death:
Sep 23, 1890 (aged 28)
Burial place:
Oakwood Cemetery
Honey Grove, TX
Powered by TF

Who is Else Buried at Oakwood Cemetery in Texas

1881 — 1881 (aged less than a year)
Birth place:
Texas
1881 — 1881 (aged less than a year)
Birth place:
Texas
1836 — 1900 (aged 64)
Birth place:
Tennessee
1843 — 1907 (aged 64)
1843 — 1912 (aged 68)
Birth place:
Tennessee
1898 — 1899 (aged less than a year)
Birth place:
Texas
1889 — 1954 (aged 64)
Birth place:
Harrisburg, AR
1922 — 1998 (aged 75)
Birth place:
Nevada, TX
1927 — 1998 (aged 70)
Birth place:
Petty, TX
1892 — 1901 (aged 8)
1937 — 2011 (aged 73)
Birth place:
Omaha, TX
1949 — 1950 (aged less than a year)
1940 — 2015 (aged 75)
1893 — 1905 (aged 12)
1899 — 1899 (aged less than a year)
Birth place:
Texas
1864 — 1878 (aged 14)
1884 — 1941 (aged 56)
Birth place:
Tennessee
1829 — 1887 (aged 57)

Recently Added Memorials

FAQ

When was Laban F Bryant born?

Laban Bryant was born on February 11, 1862

When did is Laban F Bryant pass away?

Laban Bryant passed away in September 23, 1890

Where is Laban F Bryant buried?

Laban Bryant is interred in Honey Grove, TX

At what age did Laban F Bryant pass away?

Laban Bryant passed away at the age of 28