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John Alexander Slaybaugh 18301899

Born on Jun 22, 1830 John Alexander Slaybaugh passed away on May 24, 1899, at the age of 68 and was buried in Highland Cemetery in Bayard, IA. John Alexander Slaybaugh had 6 children: William Francis Slaybaugh, Josiah Henry Slaybaugh, Elijah A Slaybaugh, George Franklin Slaybaugh, Jane D. "jennie" Slaybaugh Parry, Lois A. Slaybaugh Kearns.

Birth:
Jun 22, 1830
Death:
May 24, 1899 (aged 68)
Born in:
Pennsylvania
Burial place:
Highland Cemetery
Bayard, IA

Passed away Relatives of John Alexander Slaybaugh

children

18561932 (aged 75)
Birth place:
Panora, IA
Burial place:
Address:
State Street (Iowa State Hwy, Panora, IA 50216
18561941 (aged 84)
Birth place:
Guthrie Center, IA
Burial place:
Address:
Macksburg, IA
18591900 (aged 41)
Birth place:
Iowa
Burial place:
Address:
Bayard, IA
18611939 (aged 77)
Birth place:
Guthrie Center, IA
Burial place:
Address:
Bayard, IA
18631949 (aged 86)
Burial place:
Address:
Bayard, IA
18701951 (aged 81)
Burial place:
Address:
Bayard, IA
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Who is Else Buried at Highland Cemetery in Iowa

18581908 (aged 50)
19141997 (aged 83)
18781935 (aged 56)
18391918 (aged 79)
19482014 (aged 66)
Birth place:
Grinnell, IA
18681953 (aged 84)
Birth place:
Iowa
19311976 (aged 45)
19061980 (aged 74)
Born 1929
19681968 (aged less than a year)

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FAQ

When was John Alexander Slaybaugh born?

John Slaybaugh was born on June 22, 1830

Where was John Alexander Slaybaugh born?

John Slaybaugh was born in Cumberland County, Pennsylvania

When did is John Alexander Slaybaugh pass away?

John Slaybaugh passed away in May 24, 1899

Where is John Alexander Slaybaugh buried?

John Slaybaugh is interred in Bayard, IA

At what age did John Alexander Slaybaugh pass away?

John Slaybaugh passed away at the age of 68