Howard Elliott 1835 — 1909

Born on Sep 23, 1835 Howard Elliott passed away on Apr 10, 1909, at the age of 73 and was buried in Rose Hill Cemetery in Mechanicsville, IA. Howard Elliott was married to Mary M Ferguson Elliott.

Birth:
Sep 23, 1835
Death:
Apr 10, 1909 (aged 73)
Born in:
Ohio
Plot:
Tier 8, Lot 15
Burial place:
Rose Hill Cemetery
Mechanicsville, IA

Passed away Relatives of Howard Elliott

spouses

1841 — 1927 (aged 85)
Birth place:
Pennsylvania
Burial place:
Address:
Mechanicsville, IA

Who is Else Buried at Rose Hill Cemetery in Iowa

1880 — 1957 (aged 77)
Died 1864
1872 — 1933 (aged 61)
1854 — 1942 (aged 88)
Birth place:
Mechanicsville, IA
1884 — 1967 (aged 82)
Birth place:
Mechanicsville, IA
Died 1881
1870 — 1894 (aged 24)
1845 — 1910 (aged 64)
Birth place:
Iowa
1866 — 1869 (aged 3)
Died 1922
1861 — 1930 (aged 69)
1873 — 1951 (aged 78)
Died 1892
1833 — 1901 (aged 68)
See all burial records

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FAQ

When was Howard Elliott born?

Howard Elliott was born on September 23, 1835

Where was Howard Elliott born?

Howard Elliott was born in Marion County, Ohio

When did is Howard Elliott pass away?

Howard Elliott passed away in April 10, 1909

Where is Howard Elliott buried?

Howard Elliott is interred in Mechanicsville, IA, in Plot: Tier 8, Lot 15

At what age did Howard Elliott pass away?

Howard Elliott passed away at the age of 73

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