Henry George Shultz 1828 — 1889

Born on Feb 7, 1828 Henry George Shultz passed away on Mar 5, 1889, at the age of 61 and was buried in Jefferson Cemetery in Jefferson, IA. Henry George Shultz had 2 children: George Washington Shultz, Henry Clay Shultz.

Birth:
Feb 7, 1828
Death:
Mar 5, 1889 (aged 61)
Born in:
Pennsylvania
Burial place:
Jefferson Cemetery
Jefferson, IA

Passed away Relatives of Henry George Shultz

children

1861 — 1943 (aged 82)
Birth place:
Sterling, IL
Burial place:
Address:
Jefferson, IA
1864 — 1906 (aged 42)
Birth place:
Illinois
Burial place:
Address:
Jefferson, IA

Who is Else Buried at Jefferson Cemetery in Iowa

1905 — 1988 (aged 83)
Died 1899
1849 — 1917 (aged 67)
1881 — 1938 (aged 57)
1844 — 1906 (aged 62)
1832 — 1905 (aged 73)
1900 — 1900 (aged less than a year)
1861 — 1942 (aged 81)
Birth place:
Westside, IA
1915 — 1970 (aged 55)
1917 — 1982 (aged 64)
1833 — 1913 (aged 80)
1896 — 1987 (aged 91)
1852 — 1936 (aged 84)
Birth place:
Ohio
1867 — 1909 (aged 42)
1908 — 1998 (aged 90)
1861 — 1943 (aged 82)
Birth place:
Sterling, IL
1920 — 2006 (aged 86)
Birth place:
Iowa
1902 — 1968 (aged 66)
Birth place:
Jefferson, IA
1924 — 1976 (aged 52)
1913 — 1994 (aged 80)
1913 — 1961 (aged 48)
See all burial records

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FAQ

When was Henry George Shultz born?

Henry Shultz was born on February 7, 1828

Where was Henry George Shultz born?

Henry Shultz was born in Pennsylvania

When did is Henry George Shultz pass away?

Henry Shultz passed away in March 5, 1889

Where is Henry George Shultz buried?

Henry Shultz is interred in Jefferson, IA

At what age did Henry George Shultz pass away?

Henry Shultz passed away at the age of 61

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