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Harry Howard 1881 — 1892

Born on Oct 2, 1881 to William Howard and Jane E Hartley Howard. Harry Howard passed away on May 1, 1892, at the age of 10 and was buried in Sabina Cemetery in Clinton County, OH.

Birth:
Oct 2, 1881
Death:
May 1, 1892 (aged 10)
Burial place:
Sabina Cemetery
Sabina, OH

Passed away Relatives of Harry Howard

parents

1844 — 1920 (aged 75)
Birth place:
Ohio
Burial place:
Address:
Sabina, OH
1850 — 1925 (aged 75)
Birth place:
Ohio
Burial place:
Address:
Sabina, OH

siblings

1871 — 1943 (aged 72)
Birth place:
Ohio
Burial place:
Address:
Sabina, OH
1873 — 1892 (aged 18)
Burial place:
Address:
Sabina, OH
Harry Howard
Died 1892
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Who is Else Buried at Sabina Cemetery in Ohio

1881 — 1919 (aged 37)
Birth place:
Ohio
1850 — 1931 (aged 81)
Birth place:
Ohio
1844 — 1920 (aged 75)
Birth place:
Ohio
1869 — 1915 (aged 46)
Birth place:
Sabina, OH
1952 — 2013 (aged 60)
Birth place:
Rarden, OH
1886 — 1980 (aged 93)
Birth place:
Sabina, OH
1848 — 1934 (aged 85)
Birth place:
Ohio
1858 — 1930 (aged 72)
Birth place:
Ohio
1888 — 1968 (aged 80)
1878 — 1926 (aged 47)
Birth place:
Ohio
1909 — 1972 (aged 62)
1867 — 1956 (aged 89)
1869 — 1947 (aged 78)
Birth place:
Ohio
1923 — 2000 (aged 76)
Birth place:
Ohio
1836 — 1906 (aged 70)
1838 — 1910 (aged 72)
See all burial records

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FAQ

When was Harry Howard born?

Harry Howard was born on October 2, 1881

When did is Harry Howard pass away?

Harry Howard passed away in May 1, 1892

Where is Harry Howard buried?

Harry Howard is interred in Sabina, OH

At what age did Harry Howard pass away?

Harry Howard passed away at the age of 10

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