George Washington Seymour 1829 — 1898
Born on Oct 6, 1829 George Washington Seymour passed away on May 10, 1898, at the age of 68 and was buried in McDougal Cemetery in Canadian, OK. George Washington Seymour had 1 children: Andrew Jackson Seymour.
- Birth:
- Oct 6, 1829
- Death:
- May 10, 1898 (aged 68)
- Born in:
- Georgia
- Burial place:
-
McDougal Cemetery
Canadian, OK
Passed away Relatives of George Washington Seymour
children
Andrew Jackson Seymour
1875 — 1902
(aged 26)
Who is Else Buried at McDougal Cemetery in Oklahoma
Charles H. Shaffer
1940 — 1997
(aged 56)
Henry Joseph Shaffer
Born 1892
Orville "kook" Shaffer
1933 — 1995
(aged 62)
Hervy R. Smith
1832 — 1909
(aged 76)
Zimry T. Smith
1856 — 1906
(aged 49)
Mary L. Speer
1883 — 1884
(aged 1)
Mary H. Stamps
1852 — 1940
(aged 88)
John Surber
1890 — 1914
(aged 24)
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FAQ
When was George Washington Seymour born?
George Seymour was born on October 6, 1829
Where was George Washington Seymour born?
George Seymour was born in Georgia
When did is George Washington Seymour pass away?
George Seymour passed away in May 10, 1898
Where is George Washington Seymour buried?
George Seymour is interred in Canadian, OK
At what age did George Washington Seymour pass away?
George Seymour passed away at the age of 68
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