George D. Hyatt 18661870

Born on Feb 8, 1866 to Stephen S. Hyatt George D. Hyatt passed away on Sep 10, 1870, at the age of 4 and was buried in Oakwood Cemetery in Denton, TX.

Birth:
Feb 8, 1866
Death:
Sep 10, 1870 (aged 4)
Born in:
Texas
Plot:
Sec 9
Burial place:
Oakwood Cemetery
Pr E., Denton, TX 76208

Passed away Relatives of George D. Hyatt

parents

18201867 (aged 47)
Birth place:
Wilmington, OH
Burial place:
Address:
Pr E., Denton, TX 76208

Who is Else Buried at Oakwood Cemetery in Texas

18981922 (aged 24)
Birth place:
Texas
18951960 (aged 64)
19551968 (aged 13)
19081983 (aged 75)
18841957 (aged 73)
19071990 (aged 82)
19541999 (aged 45)
18711945 (aged 73)
Died 1941
19562008 (aged 51)
19091970 (aged 61)
18871968 (aged 80)
19341997 (aged 62)
Birth place:
Texas

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FAQ

When was George D. Hyatt born?

George Hyatt was born on February 8, 1866

Where was George D. Hyatt born?

George Hyatt was born in Denton County, Texas

When did is George D. Hyatt pass away?

George Hyatt passed away in September 10, 1870

Where is George D. Hyatt buried?

George Hyatt is interred in Pr E., Denton, TX 76208, in Plot: Sec 9

At what age did George D. Hyatt pass away?

George Hyatt passed away at the age of 4