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Babe Seward 1875 — 1905

Born on Jun 18, 1875 Babe Seward passed away on May 14, 1905, at the age of 29 and was buried in Friendship Cemetery in Coryell County, TX. Babe Seward had 2 children: Rosie L Seward, Ophelia Seward.

Birth:
Jun 18, 1875
Death:
May 14, 1905 (aged 29)
Burial place:
Friendship Cemetery
Texas

Passed away Relatives of Babe Seward

children

1894 — 1905 (aged 10)
Burial place:
Address:
Texas
1903 — 1905 (aged 1)
Burial place:
Address:
Texas
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Who is Else Buried at Friendship Cemetery in Texas

1849 — 1918 (aged 68)
1835 — 1915 (aged 79)
Birth place:
Louisiana
1901 — 1901 (aged less than a year)
Died 1931
1888 — 1889 (aged 1)
1913 — 1941 (aged 28)
Birth place:
Gatesville, TX
1845 — 1913 (aged 68)
Birth place:
Tennessee
1918 — 1918 (aged less than a year)
1872 — 1918 (aged 46)
Birth place:
Missouri
1897 — 1897 (aged less than a year)
1840 — 1867 (aged 26)
1866 — 1917 (aged 51)
1931 — 1935 (aged 4)
1875 — 1890 (aged 15)
1870 — 1945 (aged 74)
1884 — 1943 (aged 58)
1859 — 1947 (aged 88)
1903 — 1905 (aged 1)
1832 — 1925 (aged 92)
1911 — 1911 (aged less than a year)
1849 — 1892 (aged 42)
1891 — 1981 (aged 89)
Birth place:
Texas
1812 — 1885 (aged 73)
Birth place:
Tennessee
Died 1884

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FAQ

When was Babe Seward born?

Babe Seward was born on June 18, 1875

When did is Babe Seward pass away?

Babe Seward passed away in May 14, 1905

Where is Babe Seward buried?

Babe Seward is interred in Coryell County, Texas

At what age did Babe Seward pass away?

Babe Seward passed away at the age of 29