Alfred Seymour 1855 — 1924

Born on 1855 to Charles Levater Seymour and Clarissa Day Seymour. Alfred Seymour passed away on 1924, at the age of 69 and was buried in Rose Hill Cemetery in Shaffton, IA.

Birth:
1855
Death:
1924 (aged 69)
Burial place:
Rose Hill Cemetery
Camanche, IA

Passed away Relatives of Alfred Seymour

parents

1818 — 1902 (aged 84)
Birth place:
New York
Burial place:
Address:
Camanche, IA
1817 — 1861 (aged 44)
Birth place:
Vermont
Burial place:
Address:
Camanche, IA

siblings

1841 — 1914 (aged 73)
Birth place:
Illinois
Burial place:
Address:
Thornburg, IA
1843 — 1883 (aged 40)
Burial place:
Address:
South-Central Portion Of Harrison County South-central portion of Harrison County, Bethany, MO
1845 — 1911 (aged 66)
Burial place:
Address:
4 Ave N & Bluff, Clinton, IA 52732
1848 — 1900 (aged 51)
Burial place:
Address:
4 Ave N & Bluff, Clinton, IA 52732
Alfred Seymour
Died 1924
1861 — 1938 (aged 77)
Burial place:
Address:
4 Ave N & Bluff, Clinton, IA 52732

Who is Else Buried at Rose Hill Cemetery in Iowa

1916 — 1991 (aged 75)
1874 — 1882 (aged 7)
1865 — 1942 (aged 77)
1874 — 1967 (aged 93)
Died 1881
Birth place:
Monson, MA
1923 — 1982 (aged 59)
1822 — 1872 (aged 49)
Birth place:
New York
1930 — 2002 (aged 72)
1937 — 2015 (aged 78)
1954 — 1996 (aged 41)
1930 — 2014 (aged 84)
1924 — 2016 (aged 91)
1867 — 1891 (aged 24)
Birth place:
Iowa
See all burial records

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FAQ

When was Alfred Seymour born?

Alfred Seymour was born on 1855

When did is Alfred Seymour pass away?

Alfred Seymour passed away in 1924

Where is Alfred Seymour buried?

Alfred Seymour is interred in Camanche, IA

At what age did Alfred Seymour pass away?

Alfred Seymour passed away at the age of 69

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