Alfred Owen Saville 1891 — 1895

Born on Aug 8, 1891 to Jesse Saville and Syotha Jane "jane" Lewis Saville. Alfred Owen Saville passed away on Nov 7, 1895, at the age of 4 and was buried in Hazelwood Cemetery in Oakland Acres, IA.

Birth:
Aug 8, 1891
Death:
Nov 7, 1895 (aged 4)
Born in:
Iowa
Burial place:
Hazelwood Cemetery
Grinnell, IA

Passed away Relatives of Alfred Owen Saville

parents

1859 — 1920 (aged 61)
Birth place:
Athens, MO
Burial place:
Address:
Grinnell, IA
1858 — 1929 (aged 70)
Birth place:
Kentucky
Burial place:
Address:
Grinnell, IA

siblings

Alfred Owen Saville
Died 1895
1895 — 1895 (aged less than a year)
Birth place:
Iowa
Burial place:
Address:
Grinnell, IA

Who is Else Buried at Hazelwood Cemetery in Iowa

1873 — 1964 (aged 91)
Birth place:
Iowa
1842 — 1912 (aged 70)
Birth place:
New Ipswich, NH
1869 — 1892 (aged 23)
1881 — 1967 (aged 86)
1887 — 1967 (aged 80)
1832 — 1869 (aged 37)
1826 — 1887 (aged 60)
1938 — 1995 (aged 56)
Birth place:
Grinnell, IA
1829 — 1896 (aged 67)
Birth place:
Mackinaw, IL
1920 — 1920 (aged less than a year)
1850 — 1925 (aged 74)
Birth place:
Iowa
1868 — 1935 (aged 66)
Birth place:
Boone, IA
1859 — 1928 (aged 69)
1859 — 1920 (aged 61)
Birth place:
Athens, MO
1840 — 1922 (aged 81)
Birth place:
Hartland, VT
1912 — 1983 (aged 71)
Birth place:
Hardy, IA
1856 — 1902 (aged 45)
1854 — 1929 (aged 75)
1889 — 1937 (aged 47)
Birth place:
Grinnell, IA
1895 — 1986 (aged 90)
Died 1992
1903 — 1976 (aged 72)
Birth place:
Grinnell, IA
See all burial records

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FAQ

When was Alfred Owen Saville born?

Alfred Saville was born on August 8, 1891

Where was Alfred Owen Saville born?

Alfred Saville was born in Poweshiek County, Iowa

When did is Alfred Owen Saville pass away?

Alfred Saville passed away in November 7, 1895

Where is Alfred Owen Saville buried?

Alfred Saville is interred in Grinnell, IA

At what age did Alfred Owen Saville pass away?

Alfred Saville passed away at the age of 4

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