Alfred I Buck 18181890

Born on Apr 17, 1818 Alfred I Buck passed away on Oct 20, 1890, at the age of 72 and was buried in Eagleville Cemetery in Ashtabula County, OH. Alfred I Buck had 4 children: Rhoda G Buck, Matilda S Buck Lane, Henry Delivan Buck, Celia Irene Buck Smith.

Birth:
Apr 17, 1818
Death:
Oct 20, 1890 (aged 72)
Burial place:
Eagleville Cemetery
Ohio

Passed away Relatives of Alfred I Buck

children

18391885 (aged 46)
Burial place:
Address:
Ohio
18501923 (aged 73)
Birth place:
Ohio
Burial place:
Address:
137 Orchard St, Geneva on the Lake, OH 44041
18531942 (aged 89)
Burial place:
Address:
Ohio
18591925 (aged 66)
Burial place:
Address:
Ohio

Who is Else Buried at Eagleville Cemetery in Ohio

18801919 (aged 38)
18751914 (aged 39)
18621953 (aged 91)
19121994 (aged 82)
19122002 (aged 90)
18841964 (aged 80)
19061956 (aged 49)
18911975 (aged 83)
18531942 (aged 89)
18551889 (aged 34)
18391885 (aged 46)
19531953 (aged less than a year)

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FAQ

When was Alfred I Buck born?

Alfred Buck was born on April 17, 1818

When did is Alfred I Buck pass away?

Alfred Buck passed away in October 20, 1890

Where is Alfred I Buck buried?

Alfred Buck is interred in Ashtabula County, Ohio

At what age did Alfred I Buck pass away?

Alfred Buck passed away at the age of 72