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Alfred Earl Vail 1883 — 1920

Born on Apr 4, 1883 to Stephen Dow Vail and Arabella Bowles Vail. Alfred Earl Vail passed away on May 8, 1920, at the age of 37 and was buried in Haven Cemetery in Tama County, IA. Alfred Earl Vail had 1 children: Stephen Earl Vail.

Birth:
Apr 4, 1883
Death:
May 8, 1920 (aged 37)
Born in:
Iowa
Burial place:
Haven Cemetery
Iowa

Passed away Relatives of Alfred Earl Vail

parents

1848 — 1932 (aged 83)
Birth place:
Ohio
Burial place:
Address:
Iowa
1853 — 1932 (aged 78)
Birth place:
Ohio
Burial place:
Address:
Iowa

children

1917 — 1918 (aged less than a year)
Birth place:
Iowa
Burial place:
Address:
Iowa

siblings

1871 — 1929 (aged 58)
Birth place:
Saint Clairsville, OH
Burial place:
Address:
Tama, IA
1876 — 1896 (aged 19)
Birth place:
Iowa
Burial place:
Address:
Iowa
1881 — 1952 (aged 71)
Birth place:
Iowa
Burial place:
Address:
Iowa
Alfred Earl Vail
Died 1920
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Who is Else Buried at Haven Cemetery in Iowa

1898 — 1898 (aged less than a year)
Birth place:
Iowa
1925 — 1943 (aged 18)
Birth place:
Iowa
1851 — 1873 (aged 21)
Birth place:
Indiana
1832 — 1888 (aged 56)
Birth place:
Kentucky
1919 — 1972 (aged 53)
Birth place:
Fremont, NE
1984 — 1984 (aged less than a year)
Birth place:
Iowa
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FAQ

When was Alfred Earl Vail born?

Alfred Vail was born on April 4, 1883

Where was Alfred Earl Vail born?

Alfred Vail was born in Tama County, Iowa

When did is Alfred Earl Vail pass away?

Alfred Vail passed away in May 8, 1920

Where is Alfred Earl Vail buried?

Alfred Vail is interred in Tama County, Iowa

At what age did Alfred Earl Vail pass away?

Alfred Vail passed away at the age of 37

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