Alexander Shaul 1823 — 1900

Born on Mar 16, 1823 Alexander Shaul passed away on May 27, 1900, at the age of 77 and was buried in Malvern Cemetery in Malvern, IA.

Birth:
Mar 16, 1823
Death:
May 27, 1900 (aged 77)
Burial place:
Malvern Cemetery
Malvern, IA

Who is Else Buried at Malvern Cemetery in Iowa

1972 — 2001 (aged 29)
1884 — 1884 (aged less than a year)
1889 — 1965 (aged 76)
1920 — 1970 (aged 49)
Birth place:
Malvern, IA
1874 — 1963 (aged 89)
1894 — 1984 (aged 89)
Birth place:
Nebraska
1895 — 1980 (aged 85)
1853 — 1922 (aged 69)
Birth place:
Clearfield, PA
1811 — 1873 (aged 62)
Birth place:
New Jersey
Died 1876
1868 — 1876 (aged 8)
1832 — 1913 (aged 80)
Birth place:
New York
1871 — 1936 (aged 64)
Birth place:
Ohio
1909 — 1964 (aged 54)
Birth place:
Iowa
See all burial records

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FAQ

When was Alexander Shaul born?

Alexander Shaul was born on March 16, 1823

When did is Alexander Shaul pass away?

Alexander Shaul passed away in May 27, 1900

Where is Alexander Shaul buried?

Alexander Shaul is interred in Malvern, IA

At what age did Alexander Shaul pass away?

Alexander Shaul passed away at the age of 77

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