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Adrian E. Sarbaugh 1905 — 1950

Born on May 27, 1905 to John H. Sarbaugh and Nora E. Vernon Sarbaugh. Adrian E. Sarbaugh passed away on Nov 17, 1950, at the age of 45 and was buried in Bowers Cemetery in Zanesville, OH.

Birth:
May 27, 1905
Death:
Nov 17, 1950 (aged 45)
Born in:
Zanesville, OH
Burial place:
Bowers Cemetery
Zanesville, OH

Passed away Relatives of Adrian E. Sarbaugh

parents

1876 — 1961 (aged 84)
Birth place:
Adamsville, OH
Burial place:
Address:
Zanesville, OH
1873 — 1941 (aged 67)
Birth place:
Sonora, OH
Burial place:
Address:
Zanesville, OH

siblings

1899 — 1933 (aged 33)
Birth place:
Sonora, OH
Burial place:
Address:
Zanesville, OH
Adrian E. Sarbaugh
Died 1950
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Who is Else Buried at Bowers Cemetery in Ohio

1860 — 1940 (aged 79)
Birth place:
Ohio
1899 — 1933 (aged 33)
Birth place:
Sonora, OH
1805 — 1833 (aged 28)
1814 — 1866 (aged 52)
Birth place:
Virginia
1878 — 1878 (aged less than a year)
1843 — 1862 (aged 18)
1810 — 1848 (aged 38)
Birth place:
Virginia
1920 — 2008 (aged 87)
Birth place:
Zanesville, OH
Died 1838
Birth place:
Pennsylvania
1918 — 2003 (aged 84)
Birth place:
Stonington, CT
See all burial records

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FAQ

When was Adrian E. Sarbaugh born?

Adrian Sarbaugh was born on May 27, 1905

Where was Adrian E. Sarbaugh born?

Adrian Sarbaugh was born in Zanesville, OH

When did is Adrian E. Sarbaugh pass away?

Adrian Sarbaugh passed away in November 17, 1950

Where is Adrian E. Sarbaugh buried?

Adrian Sarbaugh is interred in Zanesville, OH

At what age did Adrian E. Sarbaugh pass away?

Adrian Sarbaugh passed away at the age of 45

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