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Abram Steenburgh 18181856

Born on Mar 17, 1818 Abram Steenburgh passed away on Jul 8, 1856, at the age of 38 and was buried in Union Cemetery in Saratoga County, NY.

Birth:
Mar 17, 1818
Death:
Jul 8, 1856 (aged 38)
Plot:
west of "Vernal Ave"
Burial place:
Union Cemetery
New York
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FAQ

When was Abram Steenburgh born?

Abram Steenburgh was born on March 17, 1818

When did is Abram Steenburgh pass away?

Abram Steenburgh passed away in July 8, 1856

Where is Abram Steenburgh buried?

Abram Steenburgh is interred in Saratoga County, New York, in Plot: west of "Vernal Ave"

At what age did Abram Steenburgh pass away?

Abram Steenburgh passed away at the age of 38