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Abram L Van Steenburgh 1848 — 1928

Born on 1848 Abram L Van Steenburgh passed away on 1928, at the age of 80 and was buried in Andes Cemetery in Andes, NY. Abram L Van Steenburgh was married to Phebe G Van Steenburgh and had 2 children: Mary Van Steenburgh, Jessie Vansteenburgh.

Birth:
1848
Death:
1928 (aged 80)
Burial place:
Andes Cemetery
Andes, NY

Passed away Relatives of Abram L Van Steenburgh

spouses

1849 — 1911 (aged 62)
Burial place:
Address:
Andes, NY

children

1869 — 1894 (aged 25)
Burial place:
Address:
Andes, NY
1877 — 1894 (aged 17)
Burial place:
Address:
Andes, NY
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Who is Else Buried at Andes Cemetery in New York

1856 — 1929 (aged 73)
1905 — 1923 (aged 18)
Born 1856
Birth place:
New York
1874 — 1875 (aged 1)
1857 — 1921 (aged 64)
1908 — 1968 (aged 59)
Birth place:
New York
1834 — 1878 (aged 44)
See all burial records

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FAQ

When was Abram L Van Steenburgh born?

Abram Steenburgh was born on 1848

When did is Abram L Van Steenburgh pass away?

Abram Steenburgh passed away in 1928

Where is Abram L Van Steenburgh buried?

Abram Steenburgh is interred in Andes, NY

At what age did Abram L Van Steenburgh pass away?

Abram Steenburgh passed away at the age of 80

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